Base | Representation |
---|---|
bin | 100000011001000111001111… |
… | …110010101100010010111011 |
3 | 200200102100120021202111122221 |
4 | 200121013033302230102323 |
5 | 122133104222120211441 |
6 | 1222554414432424511 |
7 | 42002426205241315 |
oct | 4031071762542273 |
9 | 620370507674587 |
10 | 142463256413371 |
11 | 41436367266003 |
12 | 13b8a4003a8137 |
13 | 61652c58a13aa |
14 | 27273890a47b5 |
15 | 1170be24588d1 |
hex | 8191cfcac4bb |
142463256413371 has 2 divisors, whose sum is σ = 142463256413372. Its totient is φ = 142463256413370.
The previous prime is 142463256413327. The next prime is 142463256413381. The reversal of 142463256413371 is 173314652364241.
142463256413371 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 142463256413371 - 229 = 142462719542459 is a prime.
It is not a weakly prime, because it can be changed into another prime (142463256413381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71231628206685 + 71231628206686.
It is an arithmetic number, because the mean of its divisors is an integer number (71231628206686).
Almost surely, 2142463256413371 is an apocalyptic number.
142463256413371 is a deficient number, since it is larger than the sum of its proper divisors (1).
142463256413371 is an equidigital number, since it uses as much as digits as its factorization.
142463256413371 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8709120, while the sum is 52.
The spelling of 142463256413371 in words is "one hundred forty-two trillion, four hundred sixty-three billion, two hundred fifty-six million, four hundred thirteen thousand, three hundred seventy-one".
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