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1424703097193 is a prime number
BaseRepresentation
bin10100101110110110111…
…011000000100101101001
312001012102000020011012112
4110232312323000211221
5141320242443102233
63010255523452105
7204634320341405
oct24566673004551
95035360204175
101424703097193
114aa2388358a2
121b014a227035
13a446c78824c
144cd55388105
15270d6c36048
hex14bb6ec0969

1424703097193 has 2 divisors, whose sum is σ = 1424703097194. Its totient is φ = 1424703097192.

The previous prime is 1424703097171. The next prime is 1424703097211. The reversal of 1424703097193 is 3917903074241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1165650600409 + 259052496784 = 1079653^2 + 508972^2 .

It is a cyclic number.

It is not a de Polignac number, because 1424703097193 - 212 = 1424703093097 is a prime.

It is not a weakly prime, because it can be changed into another prime (1424703097133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 712351548596 + 712351548597.

It is an arithmetic number, because the mean of its divisors is an integer number (712351548597).

Almost surely, 21424703097193 is an apocalyptic number.

It is an amenable number.

1424703097193 is a deficient number, since it is larger than the sum of its proper divisors (1).

1424703097193 is an equidigital number, since it uses as much as digits as its factorization.

1424703097193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1143072, while the sum is 50.

The spelling of 1424703097193 in words is "one trillion, four hundred twenty-four billion, seven hundred three million, ninety-seven thousand, one hundred ninety-three".