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142473355513 is a prime number
BaseRepresentation
bin1000010010110000010…
…0101110000011111001
3111121202012202100122221
42010230010232003321
54313241134334023
6145241254244041
713202423353216
oct2045404560371
9447665670587
10142473355513
1155471549805
1223742056621
1310587122878
146c77d04b0d
153a8ce3785d
hex212c12e0f9

142473355513 has 2 divisors, whose sum is σ = 142473355514. Its totient is φ = 142473355512.

The previous prime is 142473355499. The next prime is 142473355517. The reversal of 142473355513 is 315553374241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 142421702544 + 51652969 = 377388^2 + 7187^2 .

It is a cyclic number.

It is not a de Polignac number, because 142473355513 - 29 = 142473355001 is a prime.

It is a super-3 number, since 3×1424733555133 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 142473355513.

It is not a weakly prime, because it can be changed into another prime (142473355517) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71236677756 + 71236677757.

It is an arithmetic number, because the mean of its divisors is an integer number (71236677757).

Almost surely, 2142473355513 is an apocalyptic number.

It is an amenable number.

142473355513 is a deficient number, since it is larger than the sum of its proper divisors (1).

142473355513 is an equidigital number, since it uses as much as digits as its factorization.

142473355513 is an evil number, because the sum of its binary digits is even.

The product of its digits is 756000, while the sum is 43.

The spelling of 142473355513 in words is "one hundred forty-two billion, four hundred seventy-three million, three hundred fifty-five thousand, five hundred thirteen".