Base | Representation |
---|---|
bin | 1100111101011101110000… |
… | …1011010111101100101011 |
3 | 1212110022000000010011212201 |
4 | 3033113130023113230223 |
5 | 3331433201211122003 |
6 | 50150223352321031 |
7 | 3000351526420141 |
oct | 317273413275453 |
9 | 55408000104781 |
10 | 14250100489003 |
11 | 45a44852547a5 |
12 | 17219219a3177 |
13 | 7c4a17a98092 |
14 | 3739cc35b591 |
15 | 19aa27966b1d |
hex | cf5dc2d7b2b |
14250100489003 has 2 divisors, whose sum is σ = 14250100489004. Its totient is φ = 14250100489002.
The previous prime is 14250100488937. The next prime is 14250100489019. The reversal of 14250100489003 is 30098400105241.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14250100489003 is a prime.
It is not a weakly prime, because it can be changed into another prime (14250100489033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7125050244501 + 7125050244502.
It is an arithmetic number, because the mean of its divisors is an integer number (7125050244502).
Almost surely, 214250100489003 is an apocalyptic number.
14250100489003 is a deficient number, since it is larger than the sum of its proper divisors (1).
14250100489003 is an equidigital number, since it uses as much as digits as its factorization.
14250100489003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 34560, while the sum is 37.
The spelling of 14250100489003 in words is "fourteen trillion, two hundred fifty billion, one hundred million, four hundred eighty-nine thousand, three".
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