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142512601331 is a prime number
BaseRepresentation
bin1000010010111001101…
…0011011100011110011
3111121211221121020210202
42010232122123203303
54313331211220311
6145245215345415
713203411060422
oct2045632334363
9447757536722
10142512601331
1155491714771
122375322226b
13105922b4049
146c7d1dd2b9
153a915dae3b
hex212e69b8f3

142512601331 has 2 divisors, whose sum is σ = 142512601332. Its totient is φ = 142512601330.

The previous prime is 142512601291. The next prime is 142512601337. The reversal of 142512601331 is 133106215241.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-142512601331 is a prime.

It is a super-2 number, since 2×1425126013312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 142512601294 and 142512601303.

It is not a weakly prime, because it can be changed into another prime (142512601337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71256300665 + 71256300666.

It is an arithmetic number, because the mean of its divisors is an integer number (71256300666).

Almost surely, 2142512601331 is an apocalyptic number.

142512601331 is a deficient number, since it is larger than the sum of its proper divisors (1).

142512601331 is an equidigital number, since it uses as much as digits as its factorization.

142512601331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 142512601331 its reverse (133106215241), we get a palindrome (275618816572).

The spelling of 142512601331 in words is "one hundred forty-two billion, five hundred twelve million, six hundred one thousand, three hundred thirty-one".