Base | Representation |
---|---|
bin | 1100111101100101000000… |
… | …0010000110001101011011 |
3 | 1212110111000110120200212022 |
4 | 3033121100002012031123 |
5 | 3332001141304341011 |
6 | 50151144305205055 |
7 | 3000450641004152 |
oct | 317312002061533 |
9 | 55414013520768 |
10 | 14252044215131 |
11 | 45a5292455a28 |
12 | 172218493078b |
13 | 7c4c6769b498 |
14 | 373b34568599 |
15 | 19aadd4108db |
hex | cf65008635b |
14252044215131 has 2 divisors, whose sum is σ = 14252044215132. Its totient is φ = 14252044215130.
The previous prime is 14252044215121. The next prime is 14252044215259. The reversal of 14252044215131 is 13151244025241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14252044215131 - 214 = 14252044198747 is a prime.
It is a super-2 number, since 2×142520442151312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14252044215091 and 14252044215100.
It is not a weakly prime, because it can be changed into another prime (14252044215121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7126022107565 + 7126022107566.
It is an arithmetic number, because the mean of its divisors is an integer number (7126022107566).
Almost surely, 214252044215131 is an apocalyptic number.
14252044215131 is a deficient number, since it is larger than the sum of its proper divisors (1).
14252044215131 is an equidigital number, since it uses as much as digits as its factorization.
14252044215131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38400, while the sum is 35.
The spelling of 14252044215131 in words is "fourteen trillion, two hundred fifty-two billion, forty-four million, two hundred fifteen thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •