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14252044215131 is a prime number
BaseRepresentation
bin1100111101100101000000…
…0010000110001101011011
31212110111000110120200212022
43033121100002012031123
53332001141304341011
650151144305205055
73000450641004152
oct317312002061533
955414013520768
1014252044215131
1145a5292455a28
12172218493078b
137c4c6769b498
14373b34568599
1519aadd4108db
hexcf65008635b

14252044215131 has 2 divisors, whose sum is σ = 14252044215132. Its totient is φ = 14252044215130.

The previous prime is 14252044215121. The next prime is 14252044215259. The reversal of 14252044215131 is 13151244025241.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14252044215131 - 214 = 14252044198747 is a prime.

It is a super-2 number, since 2×142520442151312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14252044215091 and 14252044215100.

It is not a weakly prime, because it can be changed into another prime (14252044215121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7126022107565 + 7126022107566.

It is an arithmetic number, because the mean of its divisors is an integer number (7126022107566).

Almost surely, 214252044215131 is an apocalyptic number.

14252044215131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14252044215131 is an equidigital number, since it uses as much as digits as its factorization.

14252044215131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38400, while the sum is 35.

The spelling of 14252044215131 in words is "fourteen trillion, two hundred fifty-two billion, forty-four million, two hundred fifteen thousand, one hundred thirty-one".