Base | Representation |
---|---|
bin | 1100111101100110100001… |
… | …0111101000001100011011 |
3 | 1212110112001220212100121112 |
4 | 3033121220113220030123 |
5 | 3332003010320400124 |
6 | 50151253012330535 |
7 | 3000464026324463 |
oct | 317315027501433 |
9 | 55415056770545 |
10 | 14252452512539 |
11 | 45a54819788aa |
12 | 1722279613a4b |
13 | 7c5001156697 |
14 | 373b7288cba3 |
15 | 19ab141b290e |
hex | cf6685e831b |
14252452512539 has 2 divisors, whose sum is σ = 14252452512540. Its totient is φ = 14252452512538.
The previous prime is 14252452512527. The next prime is 14252452512563. The reversal of 14252452512539 is 93521525425241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14252452512539 - 24 = 14252452512523 is a prime.
It is not a weakly prime, because it can be changed into another prime (14252452512239) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7126226256269 + 7126226256270.
It is an arithmetic number, because the mean of its divisors is an integer number (7126226256270).
Almost surely, 214252452512539 is an apocalyptic number.
14252452512539 is a deficient number, since it is larger than the sum of its proper divisors (1).
14252452512539 is an equidigital number, since it uses as much as digits as its factorization.
14252452512539 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4320000, while the sum is 50.
The spelling of 14252452512539 in words is "fourteen trillion, two hundred fifty-two billion, four hundred fifty-two million, five hundred twelve thousand, five hundred thirty-nine".
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