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1425342013 = 7603187471
BaseRepresentation
bin101010011110100…
…1111111000111101
310200100000212122221
41110331033320331
510404341421023
6353234005341
750215131034
oct12475177075
93610025587
101425342013
11671628607
12339416851
131993b2554
14d742b71b
15851ed85d
hex54f4fe3d

1425342013 has 4 divisors (see below), whose sum is σ = 1425537088. Its totient is φ = 1425146940.

The previous prime is 1425342007. The next prime is 1425342047. The reversal of 1425342013 is 3102435241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1425342013 - 213 = 1425333821 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1425342073) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86133 + ... + 101338.

It is an arithmetic number, because the mean of its divisors is an integer number (356384272).

Almost surely, 21425342013 is an apocalyptic number.

It is an amenable number.

1425342013 is a deficient number, since it is larger than the sum of its proper divisors (195075).

1425342013 is an equidigital number, since it uses as much as digits as its factorization.

1425342013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 195074.

The product of its (nonzero) digits is 2880, while the sum is 25.

The square root of 1425342013 is about 37753.7019774220. The cubic root of 1425342013 is about 1125.3985782436.

Adding to 1425342013 its reverse (3102435241), we get a palindrome (4527777254).

The spelling of 1425342013 in words is "one billion, four hundred twenty-five million, three hundred forty-two thousand, thirteen".

Divisors: 1 7603 187471 1425342013