14254450433 has 2 divisors, whose sum is σ = 14254450434. Its totient is φ = 14254450432.

The previous prime is 14254450393. The next prime is 14254450439. The reversal of 14254450433 is 33405445241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10947855424 + 3306595009 = 104632^2 + 57503^2 .

It is a cyclic number.

It is not a de Polignac number, because 14254450433 - 2⁶ = 14254450369 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14254450393 and 14254450402.

It is not a weakly prime, because it can be changed into another prime (14254450439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7127225216 + 7127225217.

It is an arithmetic number, because the mean of its divisors is an integer number (7127225217).

Almost surely, 2^14254450433 is an apocalyptic number.

It is an amenable number.

14254450433 is a deficient number, since it is larger than the sum of its proper divisors (1).

14254450433 is an equidigital number, since it uses as much as digits as its factorization.

14254450433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 115200, while the sum is 35.

Adding to 14254450433 its reverse (33405445241), we get a palindrome (47659895674).

The spelling of 14254450433 in words is "fourteen billion, two hundred fifty-four million, four hundred fifty thousand, four hundred thirty-three".