Base | Representation |
---|---|
bin | 100000011010011011000111… |
… | …011110001101100111010100 |
3 | 200200201222000100121122000212 |
4 | 200122123013132031213110 |
5 | 122141043140122442213 |
6 | 1223104030450024552 |
7 | 42012064640630525 |
oct | 4032330736154724 |
9 | 620658010548025 |
10 | 142553311140308 |
11 | 41470579866272 |
12 | 13ba3953578158 |
13 | 6170947b45473 |
14 | 272b88d36a84c |
15 | 11732134e59a8 |
hex | 81a6c778d9d4 |
142553311140308 has 12 divisors (see below), whose sum is σ = 249503735416320. Its totient is φ = 71266529592792.
The previous prime is 142553311140307. The next prime is 142553311140311. The reversal of 142553311140308 is 803041113355241.
142553311140308 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (142553311140307) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2531462666 + ... + 2531518977.
It is an arithmetic number, because the mean of its divisors is an integer number (20791977951360).
Almost surely, 2142553311140308 is an apocalyptic number.
It is an amenable number.
142553311140308 is a deficient number, since it is larger than the sum of its proper divisors (106950424276012).
142553311140308 is a wasteful number, since it uses less digits than its factorization.
142553311140308 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5062988686 (or 5062988684 counting only the distinct ones).
The product of its (nonzero) digits is 172800, while the sum is 41.
Adding to 142553311140308 its reverse (803041113355241), we get a palindrome (945594424495549).
The spelling of 142553311140308 in words is "one hundred forty-two trillion, five hundred fifty-three billion, three hundred eleven million, one hundred forty thousand, three hundred eight".
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