Base | Representation |
---|---|
bin | 100000011010011011111100… |
… | …011101110011001000110011 |
3 | 200200202001022022120202222212 |
4 | 200122123330131303020303 |
5 | 122141102000224134212 |
6 | 1223104255010122335 |
7 | 42012125655003254 |
oct | 4032337435631063 |
9 | 620661268522885 |
10 | 142554200224307 |
11 | 41470995712233 |
12 | 13ba3b612803ab |
13 | 6170a5a0b9381 |
14 | 272b935484b2b |
15 | 11732665b7e22 |
hex | 81a6fc773233 |
142554200224307 has 2 divisors, whose sum is σ = 142554200224308. Its totient is φ = 142554200224306.
The previous prime is 142554200224279. The next prime is 142554200224327. The reversal of 142554200224307 is 703422002455241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 142554200224307 - 26 = 142554200224243 is a prime.
It is a super-2 number, since 2×1425542002243072 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (142554200224327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71277100112153 + 71277100112154.
It is an arithmetic number, because the mean of its divisors is an integer number (71277100112154).
Almost surely, 2142554200224307 is an apocalyptic number.
142554200224307 is a deficient number, since it is larger than the sum of its proper divisors (1).
142554200224307 is an equidigital number, since it uses as much as digits as its factorization.
142554200224307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 537600, while the sum is 41.
Adding to 142554200224307 its reverse (703422002455241), we get a palindrome (845976202679548).
The spelling of 142554200224307 in words is "one hundred forty-two trillion, five hundred fifty-four billion, two hundred million, two hundred twenty-four thousand, three hundred seven".
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