1425635333113 has 2 divisors, whose sum is σ = 1425635333114. Its totient is φ = 1425635333112.

The previous prime is 1425635333027. The next prime is 1425635333141. The reversal of 1425635333113 is 3113335365241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 755835494544 + 669799838569 = 869388^2 + 818413^2 .

It is an emirp because it is prime and its reverse (3113335365241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1425635333113 - 2¹³ = 1425635324921 is a prime.

It is a super-3 number, since 3×1425635333113³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1425635333173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 712817666556 + 712817666557.

It is an arithmetic number, because the mean of its divisors is an integer number (712817666557).

Almost surely, 2^{1425635333113} is an apocalyptic number.

It is an amenable number.

1425635333113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1425635333113 is an equidigital number, since it uses as much as digits as its factorization.

1425635333113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 291600, while the sum is 40.

The spelling of 1425635333113 in words is "one trillion, four hundred twenty-five billion, six hundred thirty-five million, three hundred thirty-three thousand, one hundred thirteen".