Base | Representation |
---|---|
bin | 11010100011110111… |
… | …10000011001111101 |
3 | 1100210202210201122221 |
4 | 31101323300121331 |
5 | 213200414134044 |
6 | 10314543005341 |
7 | 1013235633646 |
oct | 152173603175 |
9 | 40722721587 |
10 | 14259521149 |
11 | 6058145325 |
12 | 291b599851 |
13 | 14633061a3 |
14 | 993b506cd |
15 | 586ce8484 |
hex | 351ef067d |
14259521149 has 4 divisors (see below), whose sum is σ = 14562915264. Its totient is φ = 13956127036.
The previous prime is 14259521099. The next prime is 14259521161. The reversal of 14259521149 is 94112595241.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14259521149 - 213 = 14259512957 is a prime.
It is a super-3 number, since 3×142595211493 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14259521179) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 151696987 + ... + 151697080.
It is an arithmetic number, because the mean of its divisors is an integer number (3640728816).
Almost surely, 214259521149 is an apocalyptic number.
It is an amenable number.
14259521149 is a deficient number, since it is larger than the sum of its proper divisors (303394115).
14259521149 is an equidigital number, since it uses as much as digits as its factorization.
14259521149 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 303394114.
The product of its digits is 129600, while the sum is 43.
The spelling of 14259521149 in words is "fourteen billion, two hundred fifty-nine million, five hundred twenty-one thousand, one hundred forty-nine".
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