Base | Representation |
---|---|
bin | 1100111110000011010100… |
… | …1101100100001001111101 |
3 | 1212111021000202100022022020 |
4 | 3033200311031210021331 |
5 | 3332114324121434013 |
6 | 50155012124510353 |
7 | 3001156441332255 |
oct | 317406515441175 |
9 | 55437022308266 |
10 | 14260184171133 |
11 | 45a878a22539a |
12 | 17238769ab3b9 |
13 | 7c5963c048b4 |
14 | 3742a7664965 |
15 | 19ae17d54623 |
hex | cf83536427d |
14260184171133 has 16 divisors (see below), whose sum is σ = 20208607111680. Its totient is φ = 8918991015984.
The previous prime is 14260184171131. The next prime is 14260184171147. The reversal of 14260184171133 is 33117148106241.
It is a happy number.
It is not a de Polignac number, because 14260184171133 - 21 = 14260184171131 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14260184171131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1214453691 + ... + 1214465432.
It is an arithmetic number, because the mean of its divisors is an integer number (1263037944480).
Almost surely, 214260184171133 is an apocalyptic number.
It is an amenable number.
14260184171133 is a deficient number, since it is larger than the sum of its proper divisors (5948422940547).
14260184171133 is a wasteful number, since it uses less digits than its factorization.
14260184171133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2428919248.
The product of its (nonzero) digits is 96768, while the sum is 42.
The spelling of 14260184171133 in words is "fourteen trillion, two hundred sixty billion, one hundred eighty-four million, one hundred seventy-one thousand, one hundred thirty-three".
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