Base | Representation |
---|---|
bin | 1000010011010011100… |
… | …0111001001011010001 |
3 | 111122010112001012010001 |
4 | 2010310320321023101 |
5 | 4314042020002012 |
6 | 145304100210001 |
7 | 13206200424223 |
oct | 2046470711321 |
9 | 448115035101 |
10 | 142621250257 |
11 | 55537a83272 |
12 | 23783699901 |
13 | 105ab965455 |
14 | 6c8d802413 |
15 | 3a9aded357 |
hex | 2134e392d1 |
142621250257 has 2 divisors, whose sum is σ = 142621250258. Its totient is φ = 142621250256.
The previous prime is 142621250203. The next prime is 142621250273. The reversal of 142621250257 is 752052126241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 140223287296 + 2397962961 = 374464^2 + 48969^2 .
It is a cyclic number.
It is not a de Polignac number, because 142621250257 - 27 = 142621250129 is a prime.
It is not a weakly prime, because it can be changed into another prime (142621250557) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71310625128 + 71310625129.
It is an arithmetic number, because the mean of its divisors is an integer number (71310625129).
Almost surely, 2142621250257 is an apocalyptic number.
It is an amenable number.
142621250257 is a deficient number, since it is larger than the sum of its proper divisors (1).
142621250257 is an equidigital number, since it uses as much as digits as its factorization.
142621250257 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 67200, while the sum is 37.
Adding to 142621250257 its reverse (752052126241), we get a palindrome (894673376498).
The spelling of 142621250257 in words is "one hundred forty-two billion, six hundred twenty-one million, two hundred fifty thousand, two hundred fifty-seven".
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