Base | Representation |
---|---|
bin | 1100111111010100000110… |
… | …1110010001000001000011 |
3 | 1212120100000000000000002111 |
4 | 3033311001232101001003 |
5 | 3332443231420002223 |
6 | 50213000000000151 |
7 | 3002555011464256 |
oct | 317650156210103 |
9 | 55510000000074 |
10 | 14281868906563 |
11 | 46069a7741045 |
12 | 1727b09000057 |
13 | 7c7a0b642bab |
14 | 3753635bb09d |
15 | 19b78695b30d |
hex | cfd41b91043 |
14281868906563 has 2 divisors, whose sum is σ = 14281868906564. Its totient is φ = 14281868906562.
The previous prime is 14281868906497. The next prime is 14281868906579. The reversal of 14281868906563 is 36560986818241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14281868906563 - 237 = 14144429953091 is a prime.
It is not a weakly prime, because it can be changed into another prime (14281868903563) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7140934453281 + 7140934453282.
It is an arithmetic number, because the mean of its divisors is an integer number (7140934453282).
Almost surely, 214281868906563 is an apocalyptic number.
14281868906563 is a deficient number, since it is larger than the sum of its proper divisors (1).
14281868906563 is an equidigital number, since it uses as much as digits as its factorization.
14281868906563 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 119439360, while the sum is 67.
Subtracting from 14281868906563 its sum of digits (67), we obtain a 4-th power (14281868906496 = 19444).
The spelling of 14281868906563 in words is "fourteen trillion, two hundred eighty-one billion, eight hundred sixty-eight million, nine hundred six thousand, five hundred sixty-three".
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