Base | Representation |
---|---|
bin | 1100111111011010010100… |
… | …0111110100111000111001 |
3 | 1212120111022012222010212002 |
4 | 3033312211013310320321 |
5 | 3333010140324121411 |
6 | 50213433251230345 |
7 | 3002644231311641 |
oct | 317664507647071 |
9 | 55514265863762 |
10 | 14283536551481 |
11 | 460768301538a |
12 | 17282b35a83b5 |
13 | 7c7c15ca1532 |
14 | 375480c7d521 |
15 | 19b83306d33b |
hex | cfda51f4e39 |
14283536551481 has 2 divisors, whose sum is σ = 14283536551482. Its totient is φ = 14283536551480.
The previous prime is 14283536551447. The next prime is 14283536551589. The reversal of 14283536551481 is 18415563538241.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13563686117881 + 719850433600 = 3682891^2 + 848440^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14283536551481 is a prime.
It is a super-2 number, since 2×142835365514812 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14283536551441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7141768275740 + 7141768275741.
It is an arithmetic number, because the mean of its divisors is an integer number (7141768275741).
Almost surely, 214283536551481 is an apocalyptic number.
It is an amenable number.
14283536551481 is a deficient number, since it is larger than the sum of its proper divisors (1).
14283536551481 is an equidigital number, since it uses as much as digits as its factorization.
14283536551481 is an evil number, because the sum of its binary digits is even.
The product of its digits is 13824000, while the sum is 56.
The spelling of 14283536551481 in words is "fourteen trillion, two hundred eighty-three billion, five hundred thirty-six million, five hundred fifty-one thousand, four hundred eighty-one".
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