Base | Representation |
---|---|
bin | 10100110010100111111… |
… | …101110100100010000111 |
3 | 12001120211211210222120002 |
4 | 110302213331310202013 |
5 | 141402033232041203 |
6 | 3012205105431515 |
7 | 205136454224324 |
oct | 24624775644207 |
9 | 5046754728502 |
10 | 1428747143303 |
11 | 500a23573567 |
12 | 1b0a9863b59b |
13 | a496555c03c |
14 | 4d21a4c5b4b |
15 | 27271cabd88 |
hex | 14ca7f74887 |
1428747143303 has 4 divisors (see below), whose sum is σ = 1434675554928. Its totient is φ = 1422818731680.
The previous prime is 1428747143297. The next prime is 1428747143323. The reversal of 1428747143303 is 3033417478241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1428747143303 - 24 = 1428747143287 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1428747143323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2964205451 + ... + 2964205932.
It is an arithmetic number, because the mean of its divisors is an integer number (358668888732).
Almost surely, 21428747143303 is an apocalyptic number.
1428747143303 is a deficient number, since it is larger than the sum of its proper divisors (5928411625).
1428747143303 is an equidigital number, since it uses as much as digits as its factorization.
1428747143303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5928411624.
The product of its (nonzero) digits is 1354752, while the sum is 47.
The spelling of 1428747143303 in words is "one trillion, four hundred twenty-eight billion, seven hundred forty-seven million, one hundred forty-three thousand, three hundred three".
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