Base | Representation |
---|---|
bin | 10100110010111111010… |
… | …110001111000100001011 |
3 | 12001121212011221200012112 |
4 | 110302333112033010023 |
5 | 141403334142410103 |
6 | 3012312041332535 |
7 | 205152256426403 |
oct | 24627726170413 |
9 | 5047764850175 |
10 | 1429139419403 |
11 | 501104a43393 |
12 | 1b0b87a9714b |
13 | a49c88c7a87 |
14 | 4d256639803 |
15 | 27296446cd8 |
hex | 14cbf58f10b |
1429139419403 has 2 divisors, whose sum is σ = 1429139419404. Its totient is φ = 1429139419402.
The previous prime is 1429139419397. The next prime is 1429139419447. The reversal of 1429139419403 is 3049149319241.
It is a weak prime.
It is an emirp because it is prime and its reverse (3049149319241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1429139419403 - 212 = 1429139415307 is a prime.
It is not a weakly prime, because it can be changed into another prime (1429139419483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 714569709701 + 714569709702.
It is an arithmetic number, because the mean of its divisors is an integer number (714569709702).
Almost surely, 21429139419403 is an apocalyptic number.
1429139419403 is a deficient number, since it is larger than the sum of its proper divisors (1).
1429139419403 is an equidigital number, since it uses as much as digits as its factorization.
1429139419403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 839808, while the sum is 50.
The spelling of 1429139419403 in words is "one trillion, four hundred twenty-nine billion, one hundred thirty-nine million, four hundred nineteen thousand, four hundred three".
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