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143002551142 = 2116500115961
BaseRepresentation
bin1000010100101110011…
…1011100001101100110
3111200010002112021121001
42011023213130031212
54320332123114032
6145410000543514
713221510425503
oct2051347341546
9450102467531
10143002551142
1155713237270
122386b321b9a
131063c95a789
146cc82da4aa
153abe61b3e7
hex214b9dc366

143002551142 has 8 divisors (see below), whose sum is σ = 234004174632. Its totient is φ = 65001159600.

The previous prime is 143002551101. The next prime is 143002551163. The reversal of 143002551142 is 241155200341.

143002551142 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a self number, because there is not a number n which added to its sum of digits gives 143002551142.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3250057959 + ... + 3250058002.

It is an arithmetic number, because the mean of its divisors is an integer number (29250521829).

Almost surely, 2143002551142 is an apocalyptic number.

143002551142 is a deficient number, since it is larger than the sum of its proper divisors (91001623490).

143002551142 is a wasteful number, since it uses less digits than its factorization.

143002551142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6500115974.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 143002551142 its reverse (241155200341), we get a palindrome (384157751483).

The spelling of 143002551142 in words is "one hundred forty-three billion, two million, five hundred fifty-one thousand, one hundred forty-two".

Divisors: 1 2 11 22 6500115961 13000231922 71501275571 143002551142