Base | Representation |
---|---|
bin | 11010101000101110… |
… | …10110110000000111 |
3 | 1100220121120001011221 |
4 | 31110113112300013 |
5 | 213241334414120 |
6 | 10323001141211 |
7 | 1014242430310 |
oct | 152427266007 |
9 | 40817501157 |
10 | 14300310535 |
11 | 6079174a65 |
12 | 293118a807 |
13 | 146b8b8114 |
14 | 99932b607 |
15 | 58a6a40aa |
hex | 3545d6c07 |
14300310535 has 8 divisors (see below), whose sum is σ = 19611854496. Its totient is φ = 9805927200.
The previous prime is 14300310473. The next prime is 14300310547. The reversal of 14300310535 is 53501300341.
14300310535 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 14300310535 - 27 = 14300310407 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 204290116 + ... + 204290185.
It is an arithmetic number, because the mean of its divisors is an integer number (2451481812).
Almost surely, 214300310535 is an apocalyptic number.
14300310535 is a deficient number, since it is larger than the sum of its proper divisors (5311543961).
14300310535 is an equidigital number, since it uses as much as digits as its factorization.
14300310535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 408580313.
The product of its (nonzero) digits is 2700, while the sum is 25.
Adding to 14300310535 its reverse (53501300341), we get a palindrome (67801610876).
The spelling of 14300310535 in words is "fourteen billion, three hundred million, three hundred ten thousand, five hundred thirty-five".
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