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14300317173113 is a prime number
BaseRepresentation
bin1101000000011000110101…
…0100110100010101111001
31212122002121200200001012222
43100012031110310111321
53333244022144014423
650225250334213425
73004110122246036
oct320061524642571
955562550601188
1014300317173113
114613804265824
12172b5b7354275
137c968b6b414a
143761d377438d
1519beb635e3c8
hexd018d534579

14300317173113 has 2 divisors, whose sum is σ = 14300317173114. Its totient is φ = 14300317173112.

The previous prime is 14300317172987. The next prime is 14300317173173. The reversal of 14300317173113 is 31137171300341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11572494974569 + 2727822198544 = 3401837^2 + 1651612^2 .

It is a cyclic number.

It is not a de Polignac number, because 14300317173113 - 216 = 14300317107577 is a prime.

It is a super-2 number, since 2×143003171731132 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14300317173173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7150158586556 + 7150158586557.

It is an arithmetic number, because the mean of its divisors is an integer number (7150158586557).

Almost surely, 214300317173113 is an apocalyptic number.

It is an amenable number.

14300317173113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14300317173113 is an equidigital number, since it uses as much as digits as its factorization.

14300317173113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15876, while the sum is 35.

Adding to 14300317173113 its reverse (31137171300341), we get a palindrome (45437488473454).

The spelling of 14300317173113 in words is "fourteen trillion, three hundred billion, three hundred seventeen million, one hundred seventy-three thousand, one hundred thirteen".