Base | Representation |
---|---|
bin | 1101000000011001001100… |
… | …0111110000010111111011 |
3 | 1212122002212110122022021201 |
4 | 3100012103013300113323 |
5 | 3333244222042143113 |
6 | 50225304130315031 |
7 | 3004112412622126 |
oct | 320062307602773 |
9 | 55562773568251 |
10 | 14300414412283 |
11 | 4613854140a7a |
12 | 172b623a28a77 |
13 | 7c96a589c10c |
14 | 3762026473bd |
15 | 19bebeb6acdd |
hex | d01931f05fb |
14300414412283 has 2 divisors, whose sum is σ = 14300414412284. Its totient is φ = 14300414412282.
The previous prime is 14300414412233. The next prime is 14300414412367. The reversal of 14300414412283 is 38221441400341.
14300414412283 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14300414412283 - 29 = 14300414411771 is a prime.
It is not a weakly prime, because it can be changed into another prime (14300414412233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7150207206141 + 7150207206142.
It is an arithmetic number, because the mean of its divisors is an integer number (7150207206142).
Almost surely, 214300414412283 is an apocalyptic number.
14300414412283 is a deficient number, since it is larger than the sum of its proper divisors (1).
14300414412283 is an equidigital number, since it uses as much as digits as its factorization.
14300414412283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 73728, while the sum is 37.
The spelling of 14300414412283 in words is "fourteen trillion, three hundred billion, four hundred fourteen million, four hundred twelve thousand, two hundred eighty-three".
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