Base | Representation |
---|---|
bin | 11010101000101111… |
… | …11001010011010011 |
3 | 1100220121211020022021 |
4 | 31110113321103103 |
5 | 213241403431201 |
6 | 10323004152311 |
7 | 1014243560014 |
oct | 152427712323 |
9 | 40817736267 |
10 | 14300452051 |
11 | 6079261316 |
12 | 2931238697 |
13 | 146b937662 |
14 | 99936700b |
15 | 58a6d0ea1 |
hex | 3545f94d3 |
14300452051 has 8 divisors (see below), whose sum is σ = 14337445824. Its totient is φ = 14263486440.
The previous prime is 14300452043. The next prime is 14300452109. The reversal of 14300452051 is 15025400341.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14300452051 - 23 = 14300452043 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14300452451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1322296 + ... + 1333066.
It is an arithmetic number, because the mean of its divisors is an integer number (1792180728).
Almost surely, 214300452051 is an apocalyptic number.
14300452051 is a deficient number, since it is larger than the sum of its proper divisors (36993773).
14300452051 is a wasteful number, since it uses less digits than its factorization.
14300452051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14081.
The product of its (nonzero) digits is 2400, while the sum is 25.
Adding to 14300452051 its reverse (15025400341), we get a palindrome (29325852392).
The spelling of 14300452051 in words is "fourteen billion, three hundred million, four hundred fifty-two thousand, fifty-one".
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