Base | Representation |
---|---|
bin | 1101000000011011100100… |
… | …0000011000001001110001 |
3 | 1212122011111202122010120002 |
4 | 3100012321000120021301 |
5 | 3333302022300343043 |
6 | 50225451153355345 |
7 | 3004134231262253 |
oct | 320067100301161 |
9 | 55564452563502 |
10 | 14301050012273 |
11 | 461404a9a4722 |
12 | 172b780868b55 |
13 | 7c977748089b |
14 | 376262c19cd3 |
15 | 19c00a86bbb8 |
hex | d01b9018271 |
14301050012273 has 2 divisors, whose sum is σ = 14301050012274. Its totient is φ = 14301050012272.
The previous prime is 14301050012267. The next prime is 14301050012281. The reversal of 14301050012273 is 37221005010341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13373590488064 + 927459524209 = 3656992^2 + 963047^2 .
It is a cyclic number.
It is not a de Polignac number, because 14301050012273 - 234 = 14283870143089 is a prime.
It is not a weakly prime, because it can be changed into another prime (14301050012213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7150525006136 + 7150525006137.
It is an arithmetic number, because the mean of its divisors is an integer number (7150525006137).
Almost surely, 214301050012273 is an apocalyptic number.
It is an amenable number.
14301050012273 is a deficient number, since it is larger than the sum of its proper divisors (1).
14301050012273 is an equidigital number, since it uses as much as digits as its factorization.
14301050012273 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 29.
The spelling of 14301050012273 in words is "fourteen trillion, three hundred one billion, fifty million, twelve thousand, two hundred seventy-three".
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