14301110433132 has 36 divisors (see below), whose sum is σ = 36150368968896. Its totient is φ = 4766991999840.

The previous prime is 14301110433109. The next prime is 14301110433187. The reversal of 14301110433132 is 23133401110341.

14301110433132 is a `hidden beast` number, since 1 + 4 + 301 + 1 + 1 + 0 + 43 + 313 + 2 = 666.

It is a tau number, because it is divible by the number of its divisors (36).

It is a junction number, because it is equal to n+sod(n) for n = 14301110433096 and 14301110433105.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2133157 + ... + 5757827.

Almost surely, 2^{14301110433132} is an apocalyptic number.

14301110433132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

14301110433132 is an abundant number, since it is smaller than the sum of its proper divisors (21849258535764).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14301110433132 is a wasteful number, since it uses less digits than its factorization.

14301110433132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3734278 (or 3734273 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 14301110433132 its reverse (23133401110341), we get a palindrome (37434511543473).

The spelling of 14301110433132 in words is "fourteen trillion, three hundred one billion, one hundred ten million, four hundred thirty-three thousand, one hundred thirty-two".