Base | Representation |
---|---|
bin | 1000010100110000100… |
… | …0111001000100110000 |
3 | 111200010201000210100201 |
4 | 2011030020321010300 |
5 | 4320341344220422 |
6 | 145410512524544 |
7 | 13221645110143 |
oct | 2051410710460 |
9 | 450121023321 |
10 | 143011320112 |
11 | 55718186551 |
12 | 23872250754 |
13 | 1064170ac0b |
14 | 6cc954005a |
15 | 3ac029e727 |
hex | 214c239130 |
143011320112 has 10 divisors (see below), whose sum is σ = 277084432748. Its totient is φ = 71505660048.
The previous prime is 143011320107. The next prime is 143011320143. The reversal of 143011320112 is 211023110341.
It is a self number, because there is not a number n which added to its sum of digits gives 143011320112.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4469103738 + ... + 4469103769.
Almost surely, 2143011320112 is an apocalyptic number.
It is an amenable number.
143011320112 is a deficient number, since it is larger than the sum of its proper divisors (134073112636).
143011320112 is an equidigital number, since it uses as much as digits as its factorization.
143011320112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8938207515 (or 8938207509 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 143011320112 its reverse (211023110341), we get a palindrome (354034430453).
The spelling of 143011320112 in words is "one hundred forty-three billion, eleven million, three hundred twenty thousand, one hundred twelve".
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