Base | Representation |
---|---|
bin | 11010101000110101… |
… | …00001100000010011 |
3 | 1100220200010020101022 |
4 | 31110122201200103 |
5 | 213242043003021 |
6 | 10323031030055 |
7 | 1014252456443 |
oct | 152432414023 |
9 | 40820106338 |
10 | 14301141011 |
11 | 6079691a03 |
12 | 293150b32b |
13 | 146bb19121 |
14 | 9994a6123 |
15 | 58a7ba1ab |
hex | 3546a1813 |
14301141011 has 2 divisors, whose sum is σ = 14301141012. Its totient is φ = 14301141010.
The previous prime is 14301141007. The next prime is 14301141037. The reversal of 14301141011 is 11014110341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14301141011 - 22 = 14301141007 is a prime.
It is a super-2 number, since 2×143011410112 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14301141311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7150570505 + 7150570506.
It is an arithmetic number, because the mean of its divisors is an integer number (7150570506).
Almost surely, 214301141011 is an apocalyptic number.
14301141011 is a deficient number, since it is larger than the sum of its proper divisors (1).
14301141011 is an equidigital number, since it uses as much as digits as its factorization.
14301141011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 14301141011 its reverse (11014110341), we get a palindrome (25315251352).
The spelling of 14301141011 in words is "fourteen billion, three hundred one million, one hundred forty-one thousand, eleven".
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