Base | Representation |
---|---|
bin | 1101000000100011100101… |
… | …0001101001011010000100 |
3 | 1212122101001202000121100201 |
4 | 3100020321101221122010 |
5 | 3333320424204214134 |
6 | 50230444510420244 |
7 | 3004241452130164 |
oct | 320107121513204 |
9 | 55571052017321 |
10 | 14303202023044 |
11 | 4614a54727220 |
12 | 1730081501684 |
13 | 7c9a2b27c13c |
14 | 3763c89645a4 |
15 | 19c0d4759914 |
hex | d0239469684 |
14303202023044 has 48 divisors (see below), whose sum is σ = 29992984519680. Its totient is φ = 5891479086240.
The previous prime is 14303202023009. The next prime is 14303202023051. The reversal of 14303202023044 is 44032020230341.
It is a super-2 number, since 2×143032020230442 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 371917584 + ... + 371956039.
It is an arithmetic number, because the mean of its divisors is an integer number (624853844160).
Almost surely, 214303202023044 is an apocalyptic number.
It is an amenable number.
14303202023044 is an abundant number, since it is smaller than the sum of its proper divisors (15689782496636).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14303202023044 is a wasteful number, since it uses less digits than its factorization.
14303202023044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 743873680 (or 743873678 counting only the distinct ones).
The product of its (nonzero) digits is 13824, while the sum is 28.
Adding to 14303202023044 its reverse (44032020230341), we get a palindrome (58335222253385).
The spelling of 14303202023044 in words is "fourteen trillion, three hundred three billion, two hundred two million, twenty-three thousand, forty-four".
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