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14303235551 = 112944837729
BaseRepresentation
bin11010101001000101…
…00000110111011111
31100220211001122112212
431110202200313133
5213243112014201
610323143551035
71014306332123
oct152442406737
940824048485
1014303235551
11607a892630
12293215b47b
13146c3a05b7
1499988d583
1558aa80abb
hex3548a0ddf

14303235551 has 8 divisors (see below), whose sum is σ = 16141582800. Its totient is φ = 12554563840.

The previous prime is 14303235503. The next prime is 14303235559. The reversal of 14303235551 is 15553230341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14303235551 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14303235559) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22418546 + ... + 22419183.

It is an arithmetic number, because the mean of its divisors is an integer number (2017697850).

Almost surely, 214303235551 is an apocalyptic number.

14303235551 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

14303235551 is a deficient number, since it is larger than the sum of its proper divisors (1838347249).

14303235551 is a wasteful number, since it uses less digits than its factorization.

14303235551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44837769.

The product of its (nonzero) digits is 27000, while the sum is 32.

Adding to 14303235551 its reverse (15553230341), we get a palindrome (29856465892).

The spelling of 14303235551 in words is "fourteen billion, three hundred three million, two hundred thirty-five thousand, five hundred fifty-one".

Divisors: 1 11 29 319 44837729 493215019 1300294141 14303235551