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14303313042211 is a prime number
BaseRepresentation
bin1101000000100011111111…
…1001001001101100100011
31212122101100110220222000201
43100020333321021230203
53333321141114322321
650230503514130031
73004244300565214
oct320107771115443
955571313828021
1014303313042211
1146150013645a6
1217300b2720917
137c9a4828035b
143763d95c340b
1519c0de389291
hexd023fe49b23

14303313042211 has 2 divisors, whose sum is σ = 14303313042212. Its totient is φ = 14303313042210.

The previous prime is 14303313042163. The next prime is 14303313042217. The reversal of 14303313042211 is 11224031330341.

14303313042211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14303313042211 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14303313042211.

It is not a weakly prime, because it can be changed into another prime (14303313042217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7151656521105 + 7151656521106.

It is an arithmetic number, because the mean of its divisors is an integer number (7151656521106).

Almost surely, 214303313042211 is an apocalyptic number.

14303313042211 is a deficient number, since it is larger than the sum of its proper divisors (1).

14303313042211 is an equidigital number, since it uses as much as digits as its factorization.

14303313042211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 14303313042211 its reverse (11224031330341), we get a palindrome (25527344372552).

The spelling of 14303313042211 in words is "fourteen trillion, three hundred three billion, three hundred thirteen million, forty-two thousand, two hundred eleven".