Base | Representation |
---|---|
bin | 1101000000100110001000… |
… | …1110111111000110000111 |
3 | 1212122102211122001100222222 |
4 | 3100021202032333012013 |
5 | 3333323331113110203 |
6 | 50231041015042555 |
7 | 3004264465016165 |
oct | 320114216770607 |
9 | 55572748040888 |
10 | 14303889191303 |
11 | 4615277601978 |
12 | 173023367045b |
13 | 7c9b0a747a8a |
14 | 376451d1c235 |
15 | 19c124c45038 |
hex | d02623bf187 |
14303889191303 has 4 divisors (see below), whose sum is σ = 14307870238368. Its totient is φ = 14299908144240.
The previous prime is 14303889191281. The next prime is 14303889191363. The reversal of 14303889191303 is 30319198830341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14303889191303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14303889191363) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1990518143 + ... + 1990525328.
It is an arithmetic number, because the mean of its divisors is an integer number (3576967559592).
Almost surely, 214303889191303 is an apocalyptic number.
14303889191303 is a deficient number, since it is larger than the sum of its proper divisors (3981047065).
14303889191303 is an equidigital number, since it uses as much as digits as its factorization.
14303889191303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3981047064.
The product of its (nonzero) digits is 1679616, while the sum is 53.
The spelling of 14303889191303 in words is "fourteen trillion, three hundred three billion, eight hundred eighty-nine million, one hundred ninety-one thousand, three hundred three".
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