14310011 has 2 divisors, whose sum is σ = 14310012. Its totient is φ = 14310010.

The previous prime is 14310001. The next prime is 14310019. The reversal of 14310011 is 11001341.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14310011 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14309974 and 14310001.

It is not a weakly prime, because it can be changed into another prime (14310019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155005 + 7155006.

It is an arithmetic number, because the mean of its divisors is an integer number (7155006).

Almost surely, 2^14310011 is an apocalyptic number.

14310011 is a deficient number, since it is larger than the sum of its proper divisors (1).

14310011 is an equidigital number, since it uses as much as digits as its factorization.

14310011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 14310011 is about 3782.8575178032. The cubic root of 14310011 is about 242.7802322448.

Adding to 14310011 its reverse (11001341), we get a palindrome (25311352).

The spelling of 14310011 in words is "fourteen million, three hundred ten thousand, eleven".