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143101156481 is a prime number
BaseRepresentation
bin1000010101000101111…
…1100101110010000001
3111200100222001221200122
42011101133211302001
54321032344001411
6145423442230025
713224115521563
oct2052137456201
9450328057618
10143101156481
1155763965988
1223898355315
131065720352a
146cd7447333
153ac80e79db
hex21517e5c81

143101156481 has 2 divisors, whose sum is σ = 143101156482. Its totient is φ = 143101156480.

The previous prime is 143101156337. The next prime is 143101156487. The reversal of 143101156481 is 184651101341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 86095296400 + 57005860081 = 293420^2 + 238759^2 .

It is a cyclic number.

It is not a de Polignac number, because 143101156481 - 230 = 142027414657 is a prime.

It is a super-2 number, since 2×1431011564812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (143101156487) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71550578240 + 71550578241.

It is an arithmetic number, because the mean of its divisors is an integer number (71550578241).

Almost surely, 2143101156481 is an apocalyptic number.

It is an amenable number.

143101156481 is a deficient number, since it is larger than the sum of its proper divisors (1).

143101156481 is an equidigital number, since it uses as much as digits as its factorization.

143101156481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 35.

The spelling of 143101156481 in words is "one hundred forty-three billion, one hundred one million, one hundred fifty-six thousand, four hundred eighty-one".