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143104350103 = 11132513986971
BaseRepresentation
bin1000010101000110101…
…1110001011110010111
3111200101012002012111221
42011101223301132113
54321034203200403
6145424034511211
713224154622461
oct2052153613627
9450335065457
10143104350103
1155765747340
1223899435507
1310657a81050
146cd7a39131
153ac8528dbd
hex2151af1797

143104350103 has 16 divisors (see below), whose sum is σ = 168792446592. Its totient is φ = 119609100000.

The previous prime is 143104350079. The next prime is 143104350113. The reversal of 143104350103 is 301053401341.

It is not a de Polignac number, because 143104350103 - 25 = 143104350071 is a prime.

It is a super-2 number, since 2×1431043501032 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143104350113) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1957593 + ... + 2029378.

It is an arithmetic number, because the mean of its divisors is an integer number (10549527912).

Almost surely, 2143104350103 is an apocalyptic number.

143104350103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

143104350103 is a deficient number, since it is larger than the sum of its proper divisors (25688096489).

143104350103 is a wasteful number, since it uses less digits than its factorization.

143104350103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3987246.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 143104350103 its reverse (301053401341), we get a palindrome (444157751444).

The spelling of 143104350103 in words is "one hundred forty-three billion, one hundred four million, three hundred fifty thousand, one hundred three".

Divisors: 1 11 13 143 251 2761 3263 35893 3986971 43856681 51830623 570136853 1000729721 11008026931 13009486373 143104350103