Base | Representation |
---|---|
bin | 1000010101000110101… |
… | …1110001011110010111 |
3 | 111200101012002012111221 |
4 | 2011101223301132113 |
5 | 4321034203200403 |
6 | 145424034511211 |
7 | 13224154622461 |
oct | 2052153613627 |
9 | 450335065457 |
10 | 143104350103 |
11 | 55765747340 |
12 | 23899435507 |
13 | 10657a81050 |
14 | 6cd7a39131 |
15 | 3ac8528dbd |
hex | 2151af1797 |
143104350103 has 16 divisors (see below), whose sum is σ = 168792446592. Its totient is φ = 119609100000.
The previous prime is 143104350079. The next prime is 143104350113. The reversal of 143104350103 is 301053401341.
It is not a de Polignac number, because 143104350103 - 25 = 143104350071 is a prime.
It is a super-2 number, since 2×1431043501032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (143104350113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1957593 + ... + 2029378.
It is an arithmetic number, because the mean of its divisors is an integer number (10549527912).
Almost surely, 2143104350103 is an apocalyptic number.
143104350103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
143104350103 is a deficient number, since it is larger than the sum of its proper divisors (25688096489).
143104350103 is a wasteful number, since it uses less digits than its factorization.
143104350103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3987246.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 143104350103 its reverse (301053401341), we get a palindrome (444157751444).
The spelling of 143104350103 in words is "one hundred forty-three billion, one hundred four million, three hundred fifty thousand, one hundred three".
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