Search a number
-
+
14310912000 = 2123537113
BaseRepresentation
bin11010101001111111…
…10011000000000000
31100221100111122122210
431110333303000000
5213302043141000
610324020302120
71014431513340
oct152477630000
940840448583
1014310912000
116084156000
122934841940
131470b5a688
1499a8cad20
1558b59a350
hex354ff3000

14310912000 has 832 divisors, whose sum is σ = 59862187008. Its totient is φ = 2973696000.

The previous prime is 14310911963. The next prime is 14310912017. The reversal of 14310912000 is 21901341.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1300991995 + ... + 1300992005.

It is an arithmetic number, because the mean of its divisors is an integer number (71949744).

Almost surely, 214310912000 is an apocalyptic number.

14310912000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 14310912000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (29931093504).

14310912000 is an abundant number, since it is smaller than the sum of its proper divisors (45551275008).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14310912000 is an frugal number, since it uses more digits than its factorization.

14310912000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 82 (or 28 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 21.

14310912000 divided by its sum of digits (21) gives a cube (681472000 = 8803).

The spelling of 14310912000 in words is "fourteen billion, three hundred ten million, nine hundred twelve thousand".