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143110321427 is a prime number
BaseRepresentation
bin1000010101001000001…
…0100011010100010011
3111200101121022120122002
42011102002203110103
54321042220241202
6145424410504215
713224256442543
oct2052202432423
9450347276562
10143110321427
1155769055717
122389b43506b
1310659091c88
146cd8751323
153ac8d08302
hex21520a3513

143110321427 has 2 divisors, whose sum is σ = 143110321428. Its totient is φ = 143110321426.

The previous prime is 143110321399. The next prime is 143110321489. The reversal of 143110321427 is 724123011341.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 143110321427 - 210 = 143110320403 is a prime.

It is a super-3 number, since 3×1431103214273 (a number of 34 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 143110321427.

It is not a weakly prime, because it can be changed into another prime (143610321427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71555160713 + 71555160714.

It is an arithmetic number, because the mean of its divisors is an integer number (71555160714).

Almost surely, 2143110321427 is an apocalyptic number.

143110321427 is a deficient number, since it is larger than the sum of its proper divisors (1).

143110321427 is an equidigital number, since it uses as much as digits as its factorization.

143110321427 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4032, while the sum is 29.

Adding to 143110321427 its reverse (724123011341), we get a palindrome (867233332768).

The spelling of 143110321427 in words is "one hundred forty-three billion, one hundred ten million, three hundred twenty-one thousand, four hundred twenty-seven".