Base | Representation |
---|---|
bin | 11010101010000001… |
… | …00100001000100111 |
3 | 1100221100212212201200 |
4 | 31111000210020213 |
5 | 213302121111010 |
6 | 10324024453543 |
7 | 1014433312155 |
oct | 152500441047 |
9 | 40840785650 |
10 | 14311113255 |
11 | 608428322a |
12 | 293491a2b3 |
13 | 1470bcb16a |
14 | 99a9403d5 |
15 | 58b5d9cc0 |
hex | 355024227 |
14311113255 has 24 divisors (see below), whose sum is σ = 24814324080. Its totient is φ = 7630010880.
The previous prime is 14311113239. The next prime is 14311113277. The reversal of 14311113255 is 55231111341.
14311113255 is a `hidden beast` number, since 14 + 311 + 11 + 325 + 5 = 666.
It is not a de Polignac number, because 14311113255 - 24 = 14311113239 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 84556 + ... + 189134.
It is an arithmetic number, because the mean of its divisors is an integer number (1033930170).
Almost surely, 214311113255 is an apocalyptic number.
14311113255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14311113255 is a deficient number, since it is larger than the sum of its proper divisors (10503210825).
14311113255 is a wasteful number, since it uses less digits than its factorization.
14311113255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 107631 (or 107628 counting only the distinct ones).
The product of its digits is 1800, while the sum is 27.
Adding to 14311113255 its reverse (55231111341), we get a palindrome (69542224596).
The spelling of 14311113255 in words is "fourteen billion, three hundred eleven million, one hundred thirteen thousand, two hundred fifty-five".
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