Base | Representation |
---|---|
bin | 11010101010000001… |
… | …11100010001001111 |
3 | 1100221101001220100000 |
4 | 31111000330101033 |
5 | 213302132241421 |
6 | 10324030535343 |
7 | 1014434203320 |
oct | 152500742117 |
9 | 40841056300 |
10 | 14311212111 |
11 | 6084340529 |
12 | 2934967553 |
13 | 1470c34161 |
14 | 99a968447 |
15 | 58b609226 |
hex | 35503c44f |
14311212111 has 24 divisors (see below), whose sum is σ = 24499855744. Its totient is φ = 8177834520.
The previous prime is 14311212107. The next prime is 14311212137. The reversal of 14311212111 is 11121211341.
14311212111 is a `hidden beast` number, since 1 + 431 + 1 + 21 + 211 + 1 = 666.
It is not a de Polignac number, because 14311212111 - 22 = 14311212107 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14311212101) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4205005 + ... + 4208406.
Almost surely, 214311212111 is an apocalyptic number.
14311212111 is a deficient number, since it is larger than the sum of its proper divisors (10188643633).
14311212111 is an frugal number, since it uses more digits than its factorization.
14311212111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8413433 (or 8413421 counting only the distinct ones).
The product of its digits is 48, while the sum is 18.
Adding to 14311212111 its reverse (11121211341), we get a palindrome (25432423452).
The spelling of 14311212111 in words is "fourteen billion, three hundred eleven million, two hundred twelve thousand, one hundred eleven".
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