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14311243134 = 23488341007
BaseRepresentation
bin11010101010000010…
…00011110101111110
31100221101010110220000
431111001003311332
5213302134240014
610324031335130
71014434362626
oct152501036576
940841113800
1014311243134
116084361871
1229349814a6
131470c45306
1499a975886
1558b613509
hex355043d7e

14311243134 has 20 divisors (see below), whose sum is σ = 32067785904. Its totient is φ = 4770414324.

The previous prime is 14311243129. The next prime is 14311243153. The reversal of 14311243134 is 43134211341.

14311243134 is a `hidden beast` number, since 14 + 311 + 24 + 313 + 4 = 666.

14311243134 is digitally balanced in base 5, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 14311243098 and 14311243107.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 44170342 + ... + 44170665.

Almost surely, 214311243134 is an apocalyptic number.

14311243134 is an abundant number, since it is smaller than the sum of its proper divisors (17756542770).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14311243134 is an equidigital number, since it uses as much as digits as its factorization.

14311243134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 88341021 (or 88341012 counting only the distinct ones).

The product of its digits is 3456, while the sum is 27.

Adding to 14311243134 its reverse (43134211341), we get a palindrome (57445454475).

The spelling of 14311243134 in words is "fourteen billion, three hundred eleven million, two hundred forty-three thousand, one hundred thirty-four".

Divisors: 1 2 3 6 9 18 27 54 81 162 88341007 176682014 265023021 530046042 795069063 1590138126 2385207189 4770414378 7155621567 14311243134