Base | Representation |
---|---|
bin | 10100110100110110000… |
… | …100101010001010100010 |
3 | 12001211000000000201102000 |
4 | 110310312010222022202 |
5 | 141421424103104024 |
6 | 3013241434304430 |
7 | 205252524225066 |
oct | 24646604521242 |
9 | 5054000021360 |
10 | 1431131300514 |
11 | 501a37345123 |
12 | 1b1442b88116 |
13 | a4c5548b856 |
14 | 4d3a4dbdaa6 |
15 | 27361253cc9 |
hex | 14d3612a2a2 |
1431131300514 has 32 divisors (see below), whose sum is σ = 3180870359040. Its totient is φ = 476956979856.
The previous prime is 1431131300509. The next prime is 1431131300549. The reversal of 1431131300514 is 4150031311341.
1431131300514 is a `hidden beast` number, since 1 + 4 + 3 + 1 + 13 + 130 + 0 + 514 = 666.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2110837 + ... + 2705160.
It is an arithmetic number, because the mean of its divisors is an integer number (99402198720).
Almost surely, 21431131300514 is an apocalyptic number.
1431131300514 is an abundant number, since it is smaller than the sum of its proper divisors (1749739058526).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1431131300514 is a wasteful number, since it uses less digits than its factorization.
1431131300514 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4821511 (or 4821505 counting only the distinct ones).
The product of its (nonzero) digits is 2160, while the sum is 27.
Adding to 1431131300514 its reverse (4150031311341), we get a palindrome (5581162611855).
The spelling of 1431131300514 in words is "one trillion, four hundred thirty-one billion, one hundred thirty-one million, three hundred thousand, five hundred fourteen".
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