Base | Representation |
---|---|
bin | 1000010101001000110… |
… | …1101000000011010010 |
3 | 111200101210210001202200 |
4 | 2011102031220003102 |
5 | 4321043441140102 |
6 | 145424553024030 |
7 | 13224323223201 |
oct | 2052215500322 |
9 | 450353701680 |
10 | 143113224402 |
11 | 5576a758775 |
12 | 238a03b5016 |
13 | 1065986a405 |
14 | 6cd8ca9238 |
15 | 3ac91cd51c |
hex | 21523680d2 |
143113224402 has 48 divisors (see below), whose sum is σ = 313486860960. Its totient is φ = 47180733696.
The previous prime is 143113224383. The next prime is 143113224421. The reversal of 143113224402 is 204422311341.
143113224402 is a `hidden beast` number, since 1 + 4 + 31 + 1 + 3 + 224 + 402 = 666.
It is an interprime number because it is at equal distance from previous prime (143113224383) and next prime (143113224421).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2632249 + ... + 2686067.
It is an arithmetic number, because the mean of its divisors is an integer number (6530976270).
Almost surely, 2143113224402 is an apocalyptic number.
143113224402 is an abundant number, since it is smaller than the sum of its proper divisors (170373636558).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
143113224402 is a wasteful number, since it uses less digits than its factorization.
143113224402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55447 (or 55444 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 27.
Adding to 143113224402 its reverse (204422311341), we get a palindrome (347535535743).
The spelling of 143113224402 in words is "one hundred forty-three billion, one hundred thirteen million, two hundred twenty-four thousand, four hundred two".
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