Base | Representation |
---|---|
bin | 10100110100110110001… |
… | …011010011111011011011 |
3 | 12001211000010022022121222 |
4 | 110310312023103323123 |
5 | 141421430024410233 |
6 | 3013241535522255 |
7 | 205252545110324 |
oct | 24646613237333 |
9 | 5054003268558 |
10 | 1431133044443 |
11 | 501a38326393 |
12 | 1b144368938b |
13 | a4c5594c56b |
14 | 4d3a531544b |
15 | 2736149a898 |
hex | 14d362d3edb |
1431133044443 has 2 divisors, whose sum is σ = 1431133044444. Its totient is φ = 1431133044442.
The previous prime is 1431133044373. The next prime is 1431133044479. The reversal of 1431133044443 is 3444403311341.
It is a strong prime.
It is an emirp because it is prime and its reverse (3444403311341) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1431133044443 - 216 = 1431132978907 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (1431133044493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715566522221 + 715566522222.
It is an arithmetic number, because the mean of its divisors is an integer number (715566522222).
Almost surely, 21431133044443 is an apocalyptic number.
1431133044443 is a deficient number, since it is larger than the sum of its proper divisors (1).
1431133044443 is an equidigital number, since it uses as much as digits as its factorization.
1431133044443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 82944, while the sum is 35.
Adding to 1431133044443 its reverse (3444403311341), we get a palindrome (4875536355784).
The spelling of 1431133044443 in words is "one trillion, four hundred thirty-one billion, one hundred thirty-three million, forty-four thousand, four hundred forty-three".
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