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1431135050113 is a prime number
BaseRepresentation
bin10100110100110110010…
…010111101100110000001
312001211000021002012220001
4110310312102331212001
5141421431033100423
63013242050520001
7205252601132626
oct24646622754601
95054007065801
101431135050113
11501a3947626a
121b1444296001
13a4c561a2452
144d3a56b834d
1527361744cad
hex14d364bd981

1431135050113 has 2 divisors, whose sum is σ = 1431135050114. Its totient is φ = 1431135050112.

The previous prime is 1431135050077. The next prime is 1431135050117. The reversal of 1431135050113 is 3110505311341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1421548290369 + 9586759744 = 1192287^2 + 97912^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1431135050113 is a prime.

It is not a weakly prime, because it can be changed into another prime (1431135050117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715567525056 + 715567525057.

It is an arithmetic number, because the mean of its divisors is an integer number (715567525057).

Almost surely, 21431135050113 is an apocalyptic number.

It is an amenable number.

1431135050113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1431135050113 is an equidigital number, since it uses as much as digits as its factorization.

1431135050113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2700, while the sum is 28.

The spelling of 1431135050113 in words is "one trillion, four hundred thirty-one billion, one hundred thirty-five million, fifty thousand, one hundred thirteen".