Base | Representation |
---|---|
bin | 100000100010100101010101… |
… | …110010011000110010110110 |
3 | 200202201120100211102211012012 |
4 | 200202211111302120302312 |
5 | 122224240030400322014 |
6 | 1224213403500524222 |
7 | 42100435303123511 |
oct | 4042452562306266 |
9 | 622646324384165 |
10 | 143114044542134 |
11 | 41667364194436 |
12 | 14074563b50672 |
13 | 61b179a655ca3 |
14 | 274aa845d3d78 |
15 | 1182ad0e4ac3e |
hex | 822955c98cb6 |
143114044542134 has 8 divisors (see below), whose sum is σ = 214671508276680. Its totient is φ = 71556875116576.
The previous prime is 143114044542121. The next prime is 143114044542149. The reversal of 143114044542134 is 431245440411341.
143114044542134 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 143114044542091 and 143114044542100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72357524 + ... + 74309079.
It is an arithmetic number, because the mean of its divisors is an integer number (26833938534585).
Almost surely, 2143114044542134 is an apocalyptic number.
143114044542134 is a deficient number, since it is larger than the sum of its proper divisors (71557463734546).
143114044542134 is a wasteful number, since it uses less digits than its factorization.
143114044542134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 147154494.
The product of its (nonzero) digits is 368640, while the sum is 41.
Adding to 143114044542134 its reverse (431245440411341), we get a palindrome (574359484953475).
The spelling of 143114044542134 in words is "one hundred forty-three trillion, one hundred fourteen billion, forty-four million, five hundred forty-two thousand, one hundred thirty-four".
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