Base | Representation |
---|---|
bin | 11010101010000011… |
… | …01100111010001101 |
3 | 1100221101110000121220 |
4 | 31111001230322031 |
5 | 213302210130331 |
6 | 10324035113553 |
7 | 1014435663213 |
oct | 152501547215 |
9 | 40841400556 |
10 | 14311411341 |
11 | 6084467187 |
12 | 2934a428b9 |
13 | 1470ca3a46 |
14 | 99a9bacb3 |
15 | 58b648296 |
hex | 35506ce8d |
14311411341 has 4 divisors (see below), whose sum is σ = 19081881792. Its totient is φ = 9540940892.
The previous prime is 14311411321. The next prime is 14311411357.
14311411341 is nontrivially palindromic in base 10.
14311411341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14311411341 - 29 = 14311410829 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14311411321) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2385235221 + ... + 2385235226.
It is an arithmetic number, because the mean of its divisors is an integer number (4770470448).
Almost surely, 214311411341 is an apocalyptic number.
It is an amenable number.
14311411341 is a deficient number, since it is larger than the sum of its proper divisors (4770470451).
14311411341 is an equidigital number, since it uses as much as digits as its factorization.
14311411341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4770470450.
The product of its digits is 576, while the sum is 24.
The spelling of 14311411341 in words is "fourteen billion, three hundred eleven million, four hundred eleven thousand, three hundred forty-one".
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