Base | Representation |
---|---|
bin | 10100110100110110101… |
… | …101111110000101011100 |
3 | 12001211000202101220200112 |
4 | 110310312231332011130 |
5 | 141421434341130022 |
6 | 3013242502345152 |
7 | 205253015251010 |
oct | 24646655760534 |
9 | 5054022356615 |
10 | 1431142130012 |
11 | 501a42471521 |
12 | 1b144672b1b8 |
13 | a4c577b0b3a |
14 | 4d3a65dc540 |
15 | 273621928e2 |
hex | 14d36b7e15c |
1431142130012 has 12 divisors (see below), whose sum is σ = 2862284260080. Its totient is φ = 613346627136.
The previous prime is 1431142129997. The next prime is 1431142130027. The reversal of 1431142130012 is 2100312411341.
It is an interprime number because it is at equal distance from previous prime (1431142129997) and next prime (1431142130027).
1431142130012 is an admirable number.
It is a super-2 number, since 2×14311421300122 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1431142130012.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25556109437 + ... + 25556109492.
It is an arithmetic number, because the mean of its divisors is an integer number (238523688340).
Almost surely, 21431142130012 is an apocalyptic number.
It is an amenable number.
1431142130012 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1431142130012 is a wasteful number, since it uses less digits than its factorization.
1431142130012 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 51112218940 (or 51112218938 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 1431142130012 its reverse (2100312411341), we get a palindrome (3531454541353).
The spelling of 1431142130012 in words is "one trillion, four hundred thirty-one billion, one hundred forty-two million, one hundred thirty thousand, twelve".
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