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143114537 is a prime number
BaseRepresentation
bin10001000011111…
…00000100101001
3100222021222020102
420201330010221
5243114131122
622111235145
73355311356
oct1041740451
9328258212
10143114537
117386a085
123bb18ab5
132385ab77
141501562d
15c86e492
hex887c129

143114537 has 2 divisors, whose sum is σ = 143114538. Its totient is φ = 143114536.

The previous prime is 143114473. The next prime is 143114561. The reversal of 143114537 is 735411341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 79370281 + 63744256 = 8909^2 + 7984^2 .

It is a cyclic number.

It is not a de Polignac number, because 143114537 - 26 = 143114473 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (143114597) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71557268 + 71557269.

It is an arithmetic number, because the mean of its divisors is an integer number (71557269).

Almost surely, 2143114537 is an apocalyptic number.

It is an amenable number.

143114537 is a deficient number, since it is larger than the sum of its proper divisors (1).

143114537 is an equidigital number, since it uses as much as digits as its factorization.

143114537 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5040, while the sum is 29.

The square root of 143114537 is about 11963.0488170867. The cubic root of 143114537 is about 523.0717314879.

Adding to 143114537 its reverse (735411341), we get a palindrome (878525878).

The spelling of 143114537 in words is "one hundred forty-three million, one hundred fourteen thousand, five hundred thirty-seven".