Base | Representation |
---|---|
bin | 11010101010000100… |
… | …10000000010110001 |
3 | 1100221101201100000211 |
4 | 31111002100002301 |
5 | 213302224231444 |
6 | 10324042144121 |
7 | 1014440132605 |
oct | 152502200261 |
9 | 40841640024 |
10 | 14311555249 |
11 | 6084555312 |
12 | 2934ab2041 |
13 | 14710243b4 |
14 | 99aa17505 |
15 | 58b675c34 |
hex | 3550900b1 |
14311555249 has 2 divisors, whose sum is σ = 14311555250. Its totient is φ = 14311555248.
The previous prime is 14311555241. The next prime is 14311555277. The reversal of 14311555249 is 94255511341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13683150625 + 628404624 = 116975^2 + 25068^2 .
It is a cyclic number.
It is not a de Polignac number, because 14311555249 - 23 = 14311555241 is a prime.
It is a super-2 number, since 2×143115552492 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14311555241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155777624 + 7155777625.
It is an arithmetic number, because the mean of its divisors is an integer number (7155777625).
Almost surely, 214311555249 is an apocalyptic number.
It is an amenable number.
14311555249 is a deficient number, since it is larger than the sum of its proper divisors (1).
14311555249 is an equidigital number, since it uses as much as digits as its factorization.
14311555249 is an evil number, because the sum of its binary digits is even.
The product of its digits is 108000, while the sum is 40.
The spelling of 14311555249 in words is "fourteen billion, three hundred eleven million, five hundred fifty-five thousand, two hundred forty-nine".
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