14312002423 has 4 divisors (see below), whose sum is σ = 14406784048. Its totient is φ = 14217220800.

The previous prime is 14312002403. The next prime is 14312002511. The reversal of 14312002423 is 32420021341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14312002423 - 2⁵ = 14312002391 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14312002394 and 14312002403.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14312002403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47390586 + ... + 47390887.

It is an arithmetic number, because the mean of its divisors is an integer number (3601696012).

Almost surely, 2^14312002423 is an apocalyptic number.

14312002423 is a deficient number, since it is larger than the sum of its proper divisors (94781625).

14312002423 is an equidigital number, since it uses as much as digits as its factorization.

14312002423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 94781624.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 14312002423 its reverse (32420021341), we get a palindrome (46732023764).

The spelling of 14312002423 in words is "fourteen billion, three hundred twelve million, two thousand, four hundred twenty-three".